Mình vướng 2 câu này, không hiểu sao nó lại ra đáp án này, mọi người giải thích giùm với.
18.You have a /27 subnet mask. Which of the following are valid hosts? (Choose three.)
A.11.244.18.63
B.90.10.170.93
C.143.187.16.56
D.192.168.15.87
E.200.45.115.159
F.216.66.11.192
Answer:
18.B, C, D. This question only looks somewhat difficult because Class A, B, and C network
addresses are listed. But they are only there to confuse you. What is a /27? 255.255.255.224.
This is the mask you will use regardless of the class of address. Take out all the subnet and
broadcast addresses and you’re left with just the valid hosts.
11.Which of the following IP addresses fall into the CIDR block of 110.68.4.0/18? (Choose three.
A.110.68.8.32
B.110.68.7.64
C.110.67.6.255
D.110.66.3.254
E.110.65.5.128
F.110.64.12.128
Answer:
11.B, C, E.
A Class A network address with a /18 is 255.255.192.0. The subnets in the third octet
are 0, 64, 128, 192. The network address in the question is 110.64.0.0, with a broadcast of
110.64.127.255, since the next subnet is 110.64.128.0. Answers B, C, and E are correct host IDs.
18.You have a /27 subnet mask. Which of the following are valid hosts? (Choose three.)
A.11.244.18.63
B.90.10.170.93
C.143.187.16.56
D.192.168.15.87
E.200.45.115.159
F.216.66.11.192
Answer:
18.B, C, D. This question only looks somewhat difficult because Class A, B, and C network
addresses are listed. But they are only there to confuse you. What is a /27? 255.255.255.224.
This is the mask you will use regardless of the class of address. Take out all the subnet and
broadcast addresses and you’re left with just the valid hosts.
11.Which of the following IP addresses fall into the CIDR block of 110.68.4.0/18? (Choose three.
A.110.68.8.32
B.110.68.7.64
C.110.67.6.255
D.110.66.3.254
E.110.65.5.128
F.110.64.12.128
Answer:
11.B, C, E.
A Class A network address with a /18 is 255.255.192.0. The subnets in the third octet
are 0, 64, 128, 192. The network address in the question is 110.64.0.0, with a broadcast of
110.64.127.255, since the next subnet is 110.64.128.0. Answers B, C, and E are correct host IDs.
Comment