Chào các anh/chị và các bạn. Minh đã gửi câu này lên diễn đàn khác, nhưng thấy lâu trả lời quá, nên mình gửi lên đây.
"Nguyên văn của nó là Tiếng Anh, nên mình copy lại. Mình lười viết lại Tiếng Việt quá, mình nghĩ mọi người trong diễn đàn này ai cũng giỏi tiếng Anh ngoại trừ mình, nên không cần thiết phải viết lại Tiéng Việt"
Nhờ mọi giải giúp. Nguyên văn như sau:
--------------------------------------
Dear all.
As you see at the picture, I see this question at page 176, question 26, ******** 640-802, Version 13
According to me, I've solved this question like that.
1 Te stKingC is Root bridge because it has its lowest MAC "In this switch internetwork"
2 a/Cumulative Root path cost of Te stKingA port that connects to Te stKingD will be 2 if it passes Te stKingD for reaching Root
b/Cumulative Root path cost of Te stKingA port that connects to Te stKingB will be 11 if it passes Te stKingB for reaching Root
c/Cumulative Root path cost of Te stKingA port that connects to Te stKingC will be 10 because speed of link is 100Mbps and it is connected directly with Te stKingC .
As a result, 2b and 2c must be blocked. Because Te stKingA port that connects to Te stKingD has lowest Cumulative Root path cost.
But why in the Te stKing selected "Te stKingA port that connects to Te stKingD" is blocked. If someone know, please explain to me.
I'm expecting for your reply.
Your sincerely
"Nguyên văn của nó là Tiếng Anh, nên mình copy lại. Mình lười viết lại Tiếng Việt quá, mình nghĩ mọi người trong diễn đàn này ai cũng giỏi tiếng Anh ngoại trừ mình, nên không cần thiết phải viết lại Tiéng Việt"
Nhờ mọi giải giúp. Nguyên văn như sau:
--------------------------------------
Dear all.
As you see at the picture, I see this question at page 176, question 26, ******** 640-802, Version 13
According to me, I've solved this question like that.
1 Te stKingC is Root bridge because it has its lowest MAC "In this switch internetwork"
2 a/Cumulative Root path cost of Te stKingA port that connects to Te stKingD will be 2 if it passes Te stKingD for reaching Root
b/Cumulative Root path cost of Te stKingA port that connects to Te stKingB will be 11 if it passes Te stKingB for reaching Root
c/Cumulative Root path cost of Te stKingA port that connects to Te stKingC will be 10 because speed of link is 100Mbps and it is connected directly with Te stKingC .
As a result, 2b and 2c must be blocked. Because Te stKingA port that connects to Te stKingD has lowest Cumulative Root path cost.
But why in the Te stKing selected "Te stKingA port that connects to Te stKingD" is blocked. If someone know, please explain to me.
I'm expecting for your reply.
Your sincerely
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